If 2x+3y=13 and xy=6, find the value of 8x^3 + 27y^3. Pls answer
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Question is quite long, pls add more points.
Step-by-step explanation:
Answered by
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793
GIVEN:-
2x+3y = 13 .............(1)
xy = 6......................(2)
TO FIND:-
The value of 8x³+27y³
SOLUTION:-
2x+3y = 13
=> (2x+3y)²= 13²
=> (2x)²+(3y)²+12xy = 169
=> (2x)²+(3y)²+12×6 = 169 from(2)
=> (2x)²+(3y)² = 97 .....(3)
Hence,
8x³+27y³
= (2x)³+(3y)³
= (2x+3y) [ (2x)²+(3y)²- 6xy)
= (13) ( 97 - 6×6) from (2) and (3)
= 13×61
= 793
FORMULA USED:-
(1) A²+B² =A²+B²+2AB
(2) A³+B³ = (A+B)(A²+B²-AB)
hope this helps you
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