Question

If 2x+3y= 20 and 3x +2y= 15 themn what is the value of x+y​

Answer 1

Answer:

7

Step-by-step explanation:

Solving by elimination method;

2x + 3y = 20 -----[A]

=> 2x +3y -20 = 0

=> 3 (2x + 3y -20) = 3*0 [Taking LCM of coefficient of x]

=> 6x + 9y -60 = 0 -----[1]

3x + 2y = 15

=> 3x + 2y - 15 = 0

=> 2 (3x +2y - 15) = 3*0 [Taking LCM of coefficient of x]

=> 6x + 4y - 30 = 0 -----[2]

Equating [1] and [2] we get;

=> 6x + 4y - 30 = 0 = 6x + 9y - 60

=> 6x + 4y - 30 = 6x + 9y - 60 [6x gets cancelled on both sides]

=> 4y - 30 =  9y - 60

=> 9y - 4y = 60 - 30

=> 5y = 30

=> y = 6

Substituting 'y' to find 'x' by equating [A]

=> 2x + 3y = 20

=> 2x + 18 = 20

=> 2x = 2

=> x = 1

We got the values of x and y as: x=1 , y=6

x + y = 1 + 6

x + y = 7