If 2x+3y= 20 and 3x +2y= 15 themn what is the value of x+y
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3
Answer:
7
Step-by-step explanation:
Solving by elimination method;
2x + 3y = 20 -----[A]
=> 2x +3y -20 = 0
=> 3 (2x + 3y -20) = 3*0 [Taking LCM of coefficient of x]
=> 6x + 9y -60 = 0 -----[1]
3x + 2y = 15
=> 3x + 2y - 15 = 0
=> 2 (3x +2y - 15) = 3*0 [Taking LCM of coefficient of x]
=> 6x + 4y - 30 = 0 -----[2]
Equating [1] and [2] we get;
=> 6x + 4y - 30 = 0 = 6x + 9y - 60
=> 6x + 4y - 30 = 6x + 9y - 60 [6x gets cancelled on both sides]
=> 4y - 30 = 9y - 60
=> 9y - 4y = 60 - 30
=> 5y = 30
=> y = 6
Substituting 'y' to find 'x' by equating [A]
=> 2x + 3y = 20
=> 2x + 18 = 20
=> 2x = 2
=> x = 1
We got the values of x and y as: x=1 , y=6
x + y = 1 + 6
x + y = 7
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