Question

If 2x + 3y = 34 and x + y/y = 13/8 , then find the value of 6x + 4y

Answer 1

This answer will help you

Ok bro

thanks for this opportunity

follow me (if you want)

Answer 2

Answer:

Required value of (6x+4y) is 62.

Step-by-step explanation:

Given,2x+3y = 34 ......(1) and

$\frac{x + y}{y} = \frac{13}{ 8} \\ \frac{x}{y} + \frac{y}{y} = \frac{13}{8} \\ \frac{x}{y} + 1 = \frac{13}{8} \\ \frac{x}{y} = \frac{13}{8} - 1 \\ \frac{x}{y} = \frac{13 - 8}{8} \\ \frac{x}{y} = \frac{5}{8} \\ x = \frac{5}{8} y....(2)$

We are putting value of x in equation (1),

$2 \times \frac{5y}{8} + 3y = 34 \\ \frac{5y}{4} + 3y = 34 \\ \frac{5y + 12y}{4} = 34 \\ \frac{17y}{4} = 34 \\ y = 34 \times \frac{4}{17} \\ y = 2 \times 4 \\ y = 8$

From equation (2),

$x = \frac{5}{8} \times 8 \\ x = 5$

Now,

$6x + 4y = 6 \times 5 + 4 \times 8 \\ = 30 + 32 \\ = 62$

Required value of (6x+4y) is 62.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ5