Question

If 2x-3y/3z+y=z-y/z-x=x+3z/2y-3x then prove that every ratio = x/y

Answer 1

Answer:

2x-3y/3z+y=z-y/z-x=x+3z/2y-3x = x/y

Step-by-step explanation:

2x-3y/3z+y=z-y/z-x=x+3z/2y-3x

Lets multiply Numerator & denominator by - 3 for middle Term

= 2x-3y/3z+y= 3y - 3z/3x - 3z = x+3z/2y-3x

on Applying equal ratio theorem  

a/b = c/d  = e/f = (a + b + c)/(d + e + f)

= (2x - 3y + 3y - 3z + x + 3z)/(3z + y + 3x - 3z + 2y - 3x)

= 3x/3y

= x/y

Hence

2x-3y/3z+y=z-y/z-x=x+3z/2y-3x = x/y