If 2x-3y/3z+y=z-y/z-x=x+3z/2y-3x then prove that every ratio = x/y
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Answer:
2x-3y/3z+y=z-y/z-x=x+3z/2y-3x = x/y
Step-by-step explanation:
2x-3y/3z+y=z-y/z-x=x+3z/2y-3x
Lets multiply Numerator & denominator by - 3 for middle Term
= 2x-3y/3z+y= 3y - 3z/3x - 3z = x+3z/2y-3x
on Applying equal ratio theorem
a/b = c/d = e/f = (a + b + c)/(d + e + f)
= (2x - 3y + 3y - 3z + x + 3z)/(3z + y + 3x - 3z + 2y - 3x)
= 3x/3y
= x/y
Hence
2x-3y/3z+y=z-y/z-x=x+3z/2y-3x = x/y
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