If 2x+3y+4z=0,then find 8x^3+27y^3+64x^3
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a+b+c=0
a³+b³+c³=3abc
a³+b³+c³-3abc=(a+b+c)(a²+b²+c² -ab-bc-ac)
a³+b³+c³-3abc=0×a²+b²+c² -ab-bc-ac
a³+b³+c³-3abc=0
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