Question

if 2x=3y=4z, then x:y:z is

Answer 1

Since 2x = 3y = 4z, we see that:
k = 2x, k = 3y, and k = 4z, for some k.

Solving these for x, y, and z yields:
x = k/2, y = k/3, and z = k/4.

Therefore:
x:y:z = (k/2):(k/3):(k/4)
= 6k:4k:3k, by multiplying all parts of the proportion by 12, the LCD
= 6:4:3, by dividing all parts by k.

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Answer 2

Step-by-step explanation:

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