Question

If 2x + 3y = 5 and 3x + 2y = 10, then x- y=



Answer with Explaination​

Answer 1

Answer:

Your answer is in attachment.

Answer 2

Step-by-step explanation:

$\implies \tt \: 2x + 3y = 5 \qquad - - - - (1)$

$\implies \tt \: 3x + 2y = 10 \qquad - - - - (2)$

$\implies \tt 2x = 5 - 3y$

$\implies \tt \: x = \dfrac{5 - 3y}{2}$

$\implies \tt \: 3 \times \bigg( \dfrac{5 - 3y}{2} \bigg) + 2y = 10$

$\implies \tt\dfrac{15 - 9y}{2} + 2y = 10$

$\implies \tt \cancel2 \times \bigg( \dfrac{15 - 9y} {\cancel{2}} \bigg) + 2(2y) = 10 \times 2$

$\implies \tt 15 - 9y + 4y = 10$

$\implies \tt - 9y + 4y = 10 - 15$

$\implies \tt - 5y = - 5$

$\implies \tt \: y = 1$

$\implies \tt x = \dfrac{5 - 3y}{2} \qquad [ \because \: y = 1]$

$\implies \tt \: x = \dfrac{5 - 3 \times 1}{2}$

$\implies \tt \: x = \cancel \dfrac{2}{2}$

$\implies \tt \: x = 1$

$\implies \tt \therefore \: x - y = 1 - 1 = 0$