If 2x+3y=5 and xy=1 find 4x^2+9y^2
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4x ^ 2 + 9y ^ 2 = 13
Step-by-step explanation:
- 2x + 3y = 5 xy = 1
(2x + 3y) ^ 2 = (2x) ^ 2 + (3y) ^ 2 + 2 * 2x + 3y
= 4x² +9g² + 12xy 2 4x² +9y² + 12x1 (5) ^ 2 = 4x ^ 2 + 9y ^ 2 + 12
25 = 4x ^ 2 + 9y ^ 2 + 12
12 - 12 = 4x ^ 2 + 9y ^ 2
13 = 4x ^ 2 + 9y ^ 2
4x ^ 2 + 9y ^ 2 = 13
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