If 2x – 3y = 5 and xy = 4. Find 4x2 + 9y2.
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Answered by
14
(2x-3y)^2=(5)^2 {squaring both side
4x^2+9y^2-12xy=25
4x^2+9y^2=25+12x4=73
4x^2+9y^2-12xy=25
4x^2+9y^2=25+12x4=73
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Answered by
4
xy=4
x=4/y
put the value of x in eq 2x-3y=5
8/y-3y=5 multiply by (y)
8-3y^2=5y
3y^2+5y-8=o
3y^2-3y+8y-8=0
3y(y-1)+8(y-1)=0
(y-1)(3y+8)=0
y=1,-8/3
then 2x-3y=5
2x-3=5
x=4
put the value of x=4 y=1
4*4^2+9*1^2
4*16+9
64+9=73
4^2+9y^2=73
x=4/y
put the value of x in eq 2x-3y=5
8/y-3y=5 multiply by (y)
8-3y^2=5y
3y^2+5y-8=o
3y^2-3y+8y-8=0
3y(y-1)+8(y-1)=0
(y-1)(3y+8)=0
y=1,-8/3
then 2x-3y=5
2x-3=5
x=4
put the value of x=4 y=1
4*4^2+9*1^2
4*16+9
64+9=73
4^2+9y^2=73
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