If 2x – 3y = 5 and xy = 4, find the value of 4x^2 + 9y^2.
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Answer:
4x^2+9y^2
=(2x) ^2+(3y) ^2
=(2x-3y) ^2+2*2x*3y
=5^2+12xy
=25+12*4
=25+48
=73
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