If 2x = 3y - 5, then find the value of 8x^3 - 27y^3- 90xy + 125.
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Answer:
0
Step-by-step explanation:
(2x-3y)^3=(-5)^3
8x^3-27y^3+18xy(2x-3y)=-125
8x^3-27y^3+18xy(-5)=-125
8x^3-27y^3-90xy+125 =0
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