Question

If 2x=3y-5, then find the value of 8x3-27y3+90xy+125

Answer 1

Answer:

0

Step-by-step explanation:

2x=3y-5

2x-3y=-5

Cube on both sides

(2x-3y)^3=(-5)^3

(a-b)^3=a^3-b^3-3ab(a-b)

8x^3-9y^3-3(2x)(3y)(2x-3y)=-125

But given 2x-3y=-5

8x^3-9y^3-18xy(-5)=-125

8x^3-9y^3+90xy+125=0