Math, asked by Tanisha4404, 1 year ago

If 2x.3y.5z=2160find value of xyz

Answers

Answered by ssbristi27
5

Answer:

2^x.3^y.5^z = 2160

=) 2^x.3^y.5^z = 2^4.3^3.5^1

=) x = 4 , y = 3 , z = 1 ( when 2 , 3 and 5 are different positive primes )

I think by 2x.3y.5z you meant by 2^x.3^y.5^z.

Answered by singhrajkumar5019
0

Step-by-step explanation:

If 2x.3y.5z=2160find value of xyz

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