If 2x= 3y= 6z, prove that 1/s+1/y-1/z=0
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Answer:
2
x
=3
y
=6
z
=k
x=log
2
ky=log
3
kz=log
6
k
x
1
=log
k
2
y
1
=log
k
3
z
1
=log
k
6
x
1
+
y
1
−
z
1
=log
k
2+log
k
3−log
k
6
=log
k
6−log
k
6
=0
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