Question

If 2x – 3y = 7 and (a + b) x – (a + b – 3) y = 4a + b represent coincident lines, then a and b satisfy the equation
A. a + 5b = 0
B. 5a + b = 0
C. a – 5b = 0
D. 5a – b = 0

Answer 1

(c) a - 5b = 0

Step-by-step explanation:

For condition of coincident lines

$\frac{a1}{a2}$=$\frac{b1}{b2}$=$\frac{c1}{c2}$

$\frac{2}{a+b}$=$\frac{-3}{-(a+b-3)}$=$\frac{7}{4a+b}$

$\frac{2}{a+b}$=$\frac{7}{4a+b}$

$8a+2b=7a=7b\\8a-7a=7a-2b\\a=5b\\a-5b=0$