Question

If 2x - 3y = 7 and (a+b) x - (a + b - 3) y = 4a + b represent coincident lines , then a and b satisfy the equation

Answer 1

Answer:

The required equation satisfy a and b is $a-5b=0$                

Step-by-step explanation:

Given : Equation $2x-3y=7$ and $(a+b)x-(a+b-3)y=4a+b$ represent coincident lines.

To find : Then a and b satisfy the equation ?

Solution :

When lines are coincident then the condition of equation $a_1x+b_1y=c_1 , a_2x+b_2y=c_2$ is

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

On comparing, The equation form is

$\frac{2}{a+b}=\frac{3}{a+b-3}=\frac{7}{4a+b}$

Now, we can equate any two equation

$\frac{2}{a+b}=\frac{7}{4a+b}$

Cross multiply,

$2(4a+b)=7(a+b)$

$8a+2b=7a+7b$

$8a-7a=7b-2b$

$a=5b$

$a-5b=0$

Therefore, The required equation satisfy a and b is $a-5b=0$

Answer 2

Step-by-step explanation:

here your answer

please mark me as brainliest..