If 2x-3y=7 ans (a+b)x-(a+b-3)y=4a+b represents coincident lines, then a and b satisfy the equation- (i) a+5b=0 (ii) 5a+b =0 (iii) a-5b=0 (iv) 5a-b=0
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a - 5b = 0
2x - 3y = 7 and (a + b)x - (a + b - 3)y = 4a + b represent coincident lines then,
2
a+b
=
3
a+b−3
=
7
4a+b
2
a+b
=
7
4a+b
7(a+b)=2(4a+b)
7a+7b=8a+2b
a−5b=0
Answer (C) a - 5b = 0
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