If 2x+3y=8 and xy=-1,then find
a) (2x-3y)^2
b) (2x+3y) (2x-3y)
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Answer:
2x+3y=8 & xy=2. So using identity (a+b)²=a²+b²+2ab (2x+3y)²=(2x)²+(3y) .
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