Question

if 2x +3y=8 and xy =2, find the values of 4x²+ 9y²​

Answer 1

2x + 3y = 8

xy = 2

(a+b)² = a² +2ab + b²

(2x+3y)² = (2x)² +2 × 2x × 3y + (3y)²

8²= 4x²+24 + 9y²

64 - 24 = 4x²+ 9y²

∴ 4x²+ 9y² = 40

Answer 2

Answer:

64

Step-by-step Explanation:

$4 {x}^{2} + 9 {y}^{2} = (2 {x} )^{2} +( 3y )^{2}$

$= (2 {x}+ 3 {y})^{2}$

$= ({8})^{2}$

$= 64$

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