Question

if 2x+3y=8 and xy=2 find value of 8x^3 +27y^3​

Answer 1

Answer:

224

Step-by-step explanation:

2x+3y=8

cubing both sides, 8x^3+27y^3+18xy(2x+3y)=512

8x^3+27y^3+18*2*8=512

8x^3+27y^3+288=512

8x^3+27y^3=512-288=224