Math, asked by curiousto04050, 10 months ago

if 2x+3y=8 and xy=2 find value of 8x^3 +27y^3

Answers

Answered by nazreenimam78601

2

Answer:

224

Step-by-step explanation:

2x+3y=8

cubing both sides, 8x^3+27y^3+18xy(2x+3y)=512

8x^3+27y^3+18*2*8=512

8x^3+27y^3+288=512

8x^3+27y^3=512-288=224

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