Question

if 2x+3y=8 and xy=2,find value of 8x^3+27y^3​

Answer 1

Answer:

2x+3y=8. XY=2. Since, (A+B)³ =a³+b³+3ab(a+B) :.(2x+3y)³=(2x)³+(2y)³+3(2x)( 3y)(2x+3y) Putting value 8³=8x³+27y³18(2)(8)