Question

if 2x+3y=8 and xy=2 then find the value of 2x-3y^3

Answer 1

Answer:

The value of $(2x-3y)^3=40$

Step-by-step explanation:

Given

          2x+3y=8 and xy=2,

formula,

            $(a+b) ^2 =a ^2 +b ^2 +2ab$

$(2x+3y) ^2 =4x ^2 +9y ^2 +2(2x)(3y)(2x+3y) ^2 =4x ^2 +9y ^2 +12xy8 ^2 =4x ^2 +9y ^2 +12(2)4x ^2 +9y ^2 =64-24=40$