Math, asked by yuvrajsingh5747, 1 year ago

If 2x+3y=8 and xy=4 find 4 X square +9 y square

Answers

Answered by nikolatesla2
0
(2x+3y)^2 = 8^2
2x^2+3x^2+2×2x×3y = 64
4x^2 +9x^2+12xy = 64
4x^2+9x^2+12×4 = 64
4x^2+9x^2 = 64-48
4x^2+9x^2 = 16
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