Question

If 2x + 3y=8 and xy = 4 then find the value of 4x^2 + 9y^2

Answer 1

$(2x + 3y) {}^{2} = 4 {x}^{2} + 9 {y}^{2} + 2(2x)(3y) \\ \\ {8}^{2} = 4 {x}^{2} + 9y {}^{2} + (2 \times 2 \times 3 \times 4) \\ 4 {x}^{2} + 9 {y}^{2} = 64 - 48 = 16$

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Answer 2

Answer:

The answer is :- 4x^2+9y^2 = 64

Step-by-step explanation:

4x^2+9y^2 = ?

2x+3y = 8

4x^2+9y^2 =

(2x+3y)*(2x+3y) =

8*8 =

64 .

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