If 2x +3y = 8 and xy = 4 then find the value of 4x*x +9y*y
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(2x+3y)^2=(2x)^2+(3y)^2+2×2×3×x×y
(8)^2=4x^2+9y^2+12xy
64=4x^2+9y^2+12×4
64-48=4x^2+9y^2
16=4x^2+9y^2
(8)^2=4x^2+9y^2+12xy
64=4x^2+9y^2+12×4
64-48=4x^2+9y^2
16=4x^2+9y^2
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