If 2x + 3y = 8 and xy = 4 then find the value of 4x2 + 9y2
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Solution :
2x+3y=8
By squaring both sides.
(2x+3y)^2=8^2
By using identity : (a+b) ^2=a^2+b^2+2ab
4x^2+9y^2+12xy =64
4x^2+9y^2+12(4)=64
4x^2+9y^2+48=64
4x^2+9y^2=64-48
4x^2+9y^2=16
2x+3y=8
By squaring both sides.
(2x+3y)^2=8^2
By using identity : (a+b) ^2=a^2+b^2+2ab
4x^2+9y^2+12xy =64
4x^2+9y^2+12(4)=64
4x^2+9y^2+48=64
4x^2+9y^2=64-48
4x^2+9y^2=16
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