if 2x+3y=8 and xy=4, then find the value of (x-1/x)
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Step-by-step explanation:
squaring on both sides
(2x+3x)^2=(8)^2 (in the form of(a+b)^2
(2x)^2+2(4)+(3x)^2=64
4x^2+8+9x^2
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Answer :
2x+3y=8 and xy=4
xy = 4
y = 4 / x
2 x + 3( 4/ x )= 8
2x + 12 /x = 8
2x² + 12 = 8 x
2x² - 8x + 12 = 0
x² - 4x + 6 = 0
the value of x are 2 + √2 i , 2 - √2i
x - 1/x = 2 + √2 i - 1/ (2 + √2 i )
= ( 1 + 4√2i )/ (2 + √2 i ) ( answer )
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