Math, asked by anuragarya39, 1 year ago

If 2x + 3y = 8 , xy =2 Find the value of 8x³ + 27y³​

Answers

Answered by aman200547
14

Answer:

2x+3y=8 then (2x+3y)^3=512 then 8x^3 +27y^3 +3×2x×3y(2x+3y)=512 then8x^3 +27y^3=512 -18xy(2x+3y)=512-18×2(8)=512-288= 224

Answered by Rishik2101
26

Answer:

The answer of this question is 224.

Step-by-step explanation:

2x + 3y = 8

Cubing both sides

(2x + 3y ) ^3 = 8^3

(2x)^3 + (3y)^3 + 3×2×3 xy( 2x + 3y) = 512

Put values as given and opening brackets

8x3 + 27y3 + 18×2 (8) = 512

8x3 + 27y3 + 288 = 512

8x3 + 27 y3 = 512 - 288

8x3 + 27y3 = 224

THEREFORE YOUR ANSWER IS 224.

i.e. 8x3 + 27y3 = 224

HOPE IT HELPS U

MARK BRAINLIEST PLS

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