If 2x + 3y = 8 , xy =2 Find the value of 8x³ + 27y³
Answers
Answered by
14
Answer:
2x+3y=8 then (2x+3y)^3=512 then 8x^3 +27y^3 +3×2x×3y(2x+3y)=512 then8x^3 +27y^3=512 -18xy(2x+3y)=512-18×2(8)=512-288= 224
Answered by
26
Answer:
The answer of this question is 224.
Step-by-step explanation:
2x + 3y = 8
Cubing both sides
(2x + 3y ) ^3 = 8^3
(2x)^3 + (3y)^3 + 3×2×3 xy( 2x + 3y) = 512
Put values as given and opening brackets
8x3 + 27y3 + 18×2 (8) = 512
8x3 + 27y3 + 288 = 512
8x3 + 27 y3 = 512 - 288
8x3 + 27y3 = 224
THEREFORE YOUR ANSWER IS 224.
i.e. 8x3 + 27y3 = 224
HOPE IT HELPS U
MARK BRAINLIEST PLS
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