Math, asked by shreypatel16, 1 year ago

If 2x+3y=8and xy=2 find the value of 8x3+27y

Answers

Answered by Jerryscherry
1

Answer:


Step-by-step explanation: 2x+3y=8

xy=2

2x=8-3y

x=8-3y/2

{8-3y/2}×y=2

8ysq-3ysq=4

3ysq-8y+4

3ysq-6y-2y+4

3y(y-2)-2(y-2)

(3y-2)(y-2)

Y=2

8+27×2

8+54=62


Answered by gati
3
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