If 2x+3y=8and xy=2 find the value of 8x3+27y
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Answer:
Step-by-step explanation: 2x+3y=8
xy=2
2x=8-3y
x=8-3y/2
{8-3y/2}×y=2
8ysq-3ysq=4
3ysq-8y+4
3ysq-6y-2y+4
3y(y-2)-2(y-2)
(3y-2)(y-2)
Y=2
8+27×2
8+54=62
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