Question

If 2x^4-ax^2+1 is multiple of 1-2x what is value of a
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Answer 1

Answer:

If 1-2x is the multiple of above equation so it will perfectly divide the equation then 1-2x=0

x=1/2

so,

2x^4-ax^2+1=0

2×(1/2) ^4-a×(1/2) ^2+1=0

1/8-a/4+1=0

9/8=a/4

a=9/2