Math, asked by deepajaiswani1971, 8 months ago

if 2x+4y=3 and x-y=1 then find the value of k for equation kx+5=y by substitution method

Answers

Answered by rituritikakumari987
2

Answer:

x = 7/6 , y = 1/6 ,k = -29/7

Attachments:
Answered by Anonymous
5

\huge\mathfrak\blue{Answer:}

Given:

  • We have been given two linear equation in two variables
  • 2x + 4y = 3 and x - y = 1

To Find:

  • We have to find the value of k in the given equation kx + 5 = y

Solution:

We have been Given two equations

\implies x - y = 1

\implies y = ( x - 1 ) _____ ( 1 )

Similarly we have

\implies 2x + 4y = 3

Putting value of y from equation ( 1 )

\implies 2x + 4 ( x - 1 ) = 3

\implies 2x + 4x - 4 = 3

\implies 6x - 4 = 3

\implies 6x = 7

\implies x = \dfrac{7}{6}

______________________________

Putting x = 7/6 in equation ( 1 ) We get

\implies y = x - 1

\implies y = \dfrac{7}{6}-1

\implies y = \dfrac{7-6}{6}

\implies y = \dfrac{1}{6}

Hence value of x = 7/6 and y = 1/6

________________________________

We have been given that

\implies kx + 5 = y

\implies \dfrac{7k}{6} + 5 =\dfrac{1}{6}

\implies \dfrac{7k + 30}{6} = \dfrac{1}{6}

\implies 7k + 30 = 1

\implies 7k = -29

\implies k = -\dfrac{29}{7}

Hence the value of k is ( -29/7 )

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