Question

If (2x + 5): (7x-6) is twice the ratio of 5:8; then find the value
of x.

Answer 1

Step-by-step explanation:

$\tt \red{ \implies2x + 5 = 5 \quad \: or \: \quad \: 7x - 6 = 8}$

$\tt \pink{ \implies \: 2x = 0 \quad or \quad \: 7x = 14}$

$\tt \blue{ \implies \: x = 0 \quad \: or \: \quad \: x = 2}$

Hope It Help You.

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Answer 2

Answer:x=10

Step-by-step explanation:

We know that

a^2/b^2 is the duplicate ratio of a/b

So now the duplicate ratio of 5/8 will be 25/64

2x+5/7x+6=25/64

128x+320=175x-128x=320+150

47x=470

x=470/47

x=10

Thus the value of x is 10