If 2x + 70° and 3x + 20° are supplementary angles determine the value of x?
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Given -
Two angles which are supplementary
Angle 1 = 2x + 70°
Angle 2 = 3x + 20°
To find -
The value of x
Solution -
♦ The sum of supplementary angles are 180°.
Now , Angle 1 + Angle 2 = 180°
→ (2x + 70°) + (3x + 20°) = 180°
→ 5x + 90° = 180°
→ 5x = 180° - 90°
→ 5x = 90°
→ x =
→ x = 18°
• Furthermore , substituting value of x so as to get the values of Angle 1 and Angle 2.
Angle 1 = 2x + 70° = 2 (18°) + 70° = 36° + 70° = 106°
Angle 2 = 3x + 20° = 3 (18°) + 20° = 54° + 20° = 74°
♦ Angle 1 + Angle 2 = 180°
♦ 106° + 74° = 180°
♦ 180° = 180°
→ Since LHS = RHS , hence proved .
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