if 2x-7y=7 ; 3x+2y=8. what is the value of x-y
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2x-7y=7; 3x+y=22
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2x−7y=7 __(1) , 3x+y=22×7
⇒21x+7y=154 __(2)
Adding (1) and (2)
2x−7y=7
21x+7y=154
______________
23x=161
x=7
2x−7y=7
2×7−7y=7
7y=14−7
y=1
∴x=7,
y=1
Answer:
=> The value of x is 7 and y is 1.
Step-by-step explanation:
The given equation is,
2x-7y=7 ...(i)
3x+y=22 ...(ii)
Now, multiply the equation ( ii ) by 7,
So we get,
=> 3x+y=22\times 7
=> 21x+7y=154 ...(iii)
Now, add the equation ( i ) and ( iii ), we get
=> 2x-7y=7
+ 21x+7y=154
--------------------------
23x=161
Divide both the sides by 23
=> x=7
So, the value of x is 7.
Now, substitute the value of x as 7 in equation ( i )
=> 2x-7y=7
=> 2( 7)-7y=7
By further calculation we get,
=> 14-7y=7
Subtract 14 from both sides,
=> -7y=-7
Now, divide -7 to both sides,
=> y = 1
So, the value of y is 1.