if 2x+7y is 11 and xy is 4 then find value of 4x^2 + 49y^2
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solution:-
given:- 2x+7y = 11 and xy = 4
=> 4x^2 + 49y^2
=( 2x )² + (7y)²
= ( 2x + 7y )² .....( 1 )
from given
2x+7y = 11
so,
squaring both sides
( 2x + 7y )² = 11²
4x² + 28xy +49y² = 121
from given
4x² + 28*(4)+49y² = 121
4x² + 49y² + 112 = 121
4x² + 49y² = 121 - 112
4x² + 49y² = 9
i hope it helps you.
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