Math, asked by nandanisingh3832, 4 months ago

 If 2x =8 ,3y = 1 and 4z = 64 then x + y +z =​

Answers

Answered by ankur902727
0

Answer:

This is the answer of yr ques

Attachments:
Answered by mitalgajeramg
1

Answer:

since 2x=8

so

x=4

since 3y=1

so

y=1/3

since 4z=64

so

z=16

now

x+y+z=4+1/3+16

since LCM=3

=(12+1+48)/3

61/3 is the ans.

please mark me brainliest

Similar questions