Question

If 2x =8 ,3y = 1 and 4z = 64 then x + y +z =




please help me......​

Answer 1

Step-by-step explanation:

• $\longrightarrow\sf 2x=8$

$\longrightarrow\sf x=\dfrac {8}{2}$

$\longrightarrow\sf x=4$

• $\longrightarrow\sf 3y=1$

$\longrightarrow\sf y=\dfrac {1}{3}$

• $\longrightarrow\sf 4z=64$

$\longrightarrow\sf z=\dfrac {64}{4}$

$\longrightarrow\sf z=16$

• $\longrightarrow\sf x+y+z$

$\longrightarrow\sf 4+16+\dfrac {1}{3}$

$\longrightarrow\sf 20+\dfrac{1}{3}$

$\longrightarrow\sf \dfrac {60+1}{3}$

$\longrightarrow\bf \dfrac {61}{3}$

Answer 2

Answer:

since,2×=8

So

X=4

since 3Y=1

So

Y=1/3

since 4z=64

so

z=16

now

x+y+z=4+1/3+16

since LCM=3

=(12+1+48)/3

hence..61/3 is the correct answer ☺️