Question

if 2x+9x+k is divisible.by (x-2) then k=​

Answer 1

$\implies\sf {x - 2 = 0}$

$\implies \sf{x = 0 + 2}$

$\therefore\sf \red{x = 2}$

_____________...

$\implies\sf{2x + 9x + k = 0}$

$\implies \sf{2 \times 2 + 9 \times 2 + k = 0}$

$\implies \sf{4 + 18 + k = 0}$

$\implies \sf{22 + k = 0}$

$\implies \sf{k = 0 - 22}$

$\therefore \sf \red { \boxed {\sf{k = - 22}}}$

Answer 2

Answer:

Step-by-step explanation:

\implies\sf {x - 2 = 0}  

\implies \sf{x = 0 + 2}  

 \therefore\sf \red{x = 2}

\implies\sf{2x + 9x + k = 0}  

\implies \sf{2 \times 2 + 9 \times 2 + k = 0}

\implies \sf{4 + 18 + k = 0}  

\implies \sf{22 + k = 0}  

 \implies \sf{k = 0 - 22}  

\therefore \sf \red { \boxed {\sf{k =  - 22}}}