If 2x=ay and 2y=bx . so find out 1/a+2)+1/b+2
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given :: 2x= ay,,,, a= 2x/y
and 2y = bx ,,,,,,,b = 2y/x
find : 1/a+2)+1/b+2
put values of a ND b in this above eqn ...
(1/(2x/y)+2) + (1/ (2y/x)+2)
( 1/(2x+2y/y)) + (1/ (2y+2x/x))
(y/ 2(x+y)) + (x/2(y+x))
y+x/2(x+y)
= 1/2
answer is 1/2 ...
I hope it will help you !!!!
and 2y = bx ,,,,,,,b = 2y/x
find : 1/a+2)+1/b+2
put values of a ND b in this above eqn ...
(1/(2x/y)+2) + (1/ (2y/x)+2)
( 1/(2x+2y/y)) + (1/ (2y+2x/x))
(y/ 2(x+y)) + (x/2(y+x))
y+x/2(x+y)
= 1/2
answer is 1/2 ...
I hope it will help you !!!!
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