If 2x+k is a factor of a polynomial 8x3+4kx2+3x+k-1 then find the value of K.
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Answer:
2x+k=0
2x=0-k
x=-k/2
p(-k/2)=8(-k/2)³+4k(-k/2)²+3(-k/2)+k-1=0
= 8(-k³/8)+4k(k²/4)+-3k/2+k-1=0
= -8k³/8+4k³/4-3k/2+k-1=0
= -k³+k³-3k/2+k-1=0
= -3k/2+k=1
= -k/2=1
= k=-2
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