Question

If 2x+k is a factor of a polynomial 8x3+4kx2+3x+k-1 then find the value of K.

Answer 1

Answer:

2x+k=0

2x=0-k

x=-k/2

p(-k/2)=8(-k/2)³+4k(-k/2)²+3(-k/2)+k-1=0

= 8(-k³/8)+4k(k²/4)+-3k/2+k-1=0

= -8k³/8+4k³/4-3k/2+k-1=0

= -k³+k³-3k/2+k-1=0

= -3k/2+k=1

= -k/2=1

= k=-2