Question

if 2x = sec A and 2/x = tan A , then 2 (x^2 - 1/x^2) = ?

Answer 1

Answer:

your required answer is 1/2

Step-by-step explanation:

given,

sec A = 2x => x = (secA)/2

tan A = 2/x => 1/x = (tan A)/2

2(x²-1/x²) => 2{(sec²A)/2² - (tan²A)/2²}

=> 2{(sec²A - tan²A)/4}

=> 1/2(sec²A - tan²A)

=> 1/2*1

=> 1/2

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