Question

if 2x=secA and 2/x=tanA, then 2(x2-1x2 )=

Answer 1

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Answer 2

Formula:-

$\underline\green{\boxed{\bf sec²θ−tan²θ=1}}$

Substitute the given values in terms of x.

$\implies\sf (2x)^{2} -\bigg(\dfrac{2}{x}\bigg)^{2} = 1 \\\\\implies4x^{2} -\dfrac{4}{x^{2} }=1 \\\\\implies4\bigg(x^{2} -\dfrac{1}{x^{2} } \bigg) = 1\\\\\implies x^{2} -\dfrac{1}{x^{2} } =\dfrac{1}{4}$

Hope it helps