Question

if 2x =secA and and 2 upon X equal tan A then the value of x square minus one upon x square​

Answer 1

Answer:

(2x)2−(x2​)2=1, substitute the given values in terms of x ⇒4x2−x24​=1. ⇒4(x2−x21​)=1. ⇒x2−x21​=41​. Was this answer helpful?

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