If 2x/(x+1)(x+2)= A/x+1 + B/x+2 then value of A is
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LHS = 2x^2+3x+4(x - 1)(x^2+2); RHS = A(x^2+2)+(Bx+C)(x-1)(x - 1)(x^2+2) LHS = RHS 2x^2 + 3x + 4 = A(x^2 + 2) + (Bx + C)(x - 1) Equating the co - efficients
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