if 2x,x+10,3x+2 are in A.P then x is equal to
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Given 2x,x+10,3x+2 are three consecutive terms in A.P
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We know that,
Difference of any two consecutive terms in A.P are equal.
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(x+10)-2x = (3x+2)-(x+10)
=> x+10-2x = 3x+2-x-10
=> 10-x=2x-8
=> -x-2x = -8-10
=> -3x = -18
Divide each term by (-3) , we. get
\implies \frac{(-3x)}{(-3)} = \frac{(-18)}{(-3)}
\implies x = 6
Therefore,
x = 6
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