If 2x , X+10 , 3x+ 2 are in A.P.,
then x is equal to
Answers
Answered by
12
Given:
• 2x , x +10 and 3x+2 are in AP .
To find :
• The value of x .
Solution :
• As we know that :
• Common difference is same in AP
=> b - a = c - b
=> 2b = a + c
Here: a = 2x , b = x + 10 and c = 3x+2
=> 2 ( x +10)= 2x + 3x +2
=> 2x + 20 = 5x +2
=> 5x - 2x = 20 -2
=> 3x = 18
=> x = 18/3
=> x = 6
Hence , the value of x is 6.
Answered by
46
Since 2x,x+10 and 3x+2 are in AP
Therefore the common difference must be same.
So,
x+10-2x=3x+2-(x+10)
-x+10=3x+2-x-10
-x+10=2x-8
-x+10-2x+8=0
-3x+18=0
-3x= -18
x= −18−3
x=6
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