Math, asked by sanika2481, 7 months ago

If 2x , X+10 , 3x+ 2 are in A.P.,
then x is equal to​

Answers

Answered by kaushik05
12

Given:

• 2x , x +10 and 3x+2 are in AP .

To find :

The value of x .

Solution :

• As we know that :

Common difference is same in AP

=> b - a = c - b

=> 2b = a + c

Here: a = 2x , b = x + 10 and c = 3x+2

=> 2 ( x +10)= 2x + 3x +2

=> 2x + 20 = 5x +2

=> 5x - 2x = 20 -2

=> 3x = 18

=> x = 18/3

=> x = 6

Hence , the value of x is 6.

Answered by ltzMsGlamorouS
46

\huge\purple{\mid{\fbox{\tt{Answer:-}}\mid}}

Since 2x,x+10 and 3x+2 are in AP

Therefore the common difference must be same.

So,

\pink\longrightarrowx+10-2x=3x+2-(x+10)

\pink\longrightarrow -x+10=3x+2-x-10

\pink\longrightarrow -x+10=2x-8

\pink\longrightarrow -x+10-2x+8=0

\pink\longrightarrow -3x+18=0

\pink\longrightarrow-3x= -18

\pink\longrightarrowx= −18−3

\green\longrightarrowx=6

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