if 2x, x+10,3x+2 are in AP , find the value of x
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Step-by-step explanation:
Since 2x,x+10 and 3x+2 are in AP
Therefore the common difference must be same.
So x+10-2x=3x+2-(x+10)
-x+10=3x+2-x-10
-x+10=2x-8
-x+10-2x+8=0
-3x+18=0
-3x=-18
x=−18−3
x=6
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