Question

if 2x,x+10, 3x+2are in A. P.,then find the value of x​

Answer 1

Since 2x,x+10 and 3x+2 are in AP

Therefore the common difference must be same.

So     x+10-2x=3x+2-(x+10)

             -x+10=3x+2-x-10

              -x+10=2x-8

             -x+10-2x+8=0

                       -3x+18=0

                              -3x=-18

                                 x=−18−3−18−3

                                x=6

Answer 2

Step-by-step explanation:

2x,x+10,3x+2 are in A.P.

→x+10-2x=common difference

→3x+2-(x+10)=common difference

→x+10-2x=3x+2-(x+10)

→10-x=3x+2-x-10

→10+10-2=3x

→18=3x

→x=18/3

→x=6

Here is ur solution...

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