Question

if 2x,X+10,3x+2are in AP. then X is equal to​

Answer 1

Answer:

Answer:

x = 6x=6

Explanation:

Given 2x,x+10,3x+2 are three consecutive terms in A.P

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We know that,

Difference of any two consecutive terms in A.P are equal.

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(x+10)-2x = (3x+2)-(x+10)

=> x+10-2x = 3x+2-x-10

=> 10-x=2x-8

=> -x-2x = -8-10

=> -3x = -18

Divide each term by (-3) , we. get

\implies \frac{(-3x)}{(-3)} = \frac{(-18)}{(-3)}⟹(−3)(−3x)=(−3)(−18)

\implies x = 6⟹x=6

Therefore,

x = 6

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Step-by-step explanation:

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Answer 2

Answer:

2x,x+10,3x+2 are in AP

Then x+10−2x=3x+2−(x+10)

−x+10=2x−8

3x=18

x=6