If 2x+y = 11, 2y+z = 12 and z+2x = 8, find the value of 2x + 3y +4z.
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Best Answer: z = -2y + 12
z = -2x + 8
-2y + 12 = -2x + 8
-y + 6 = -x + 4
-y = -x - 2
y = x + 2
y = -2x + 11
(-2x + 11) = x + 2
- 2x + 11 = x + 2
3x = 9
x = 3
y = 3 + 2 = 5
z = -2 * 5 + 12
z = -10 + 12
z = 2
So
2 * 3 + 3 * 5 + 4 * -2
6 + 15 + -8
13
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z = -2x + 8
-2y + 12 = -2x + 8
-y + 6 = -x + 4
-y = -x - 2
y = x + 2
y = -2x + 11
(-2x + 11) = x + 2
- 2x + 11 = x + 2
3x = 9
x = 3
y = 3 + 2 = 5
z = -2 * 5 + 12
z = -10 + 12
z = 2
So
2 * 3 + 3 * 5 + 4 * -2
6 + 15 + -8
13
Hope u like the ans
mark as the most intelligent one...
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